34x^2+65x-50=0

Solution for 34x^2+65x-50=0 equation:

34x^2+65x-50=0

a = 34; b = 65; c = -50;
Δ = b2-4ac
Δ = 652-4·34·(-50)
Δ = 11025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{11025}=105$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(65)-105}{2*34}=\frac{-170}{68}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(65)+105}{2*34}=\frac{40}{68}
=10/17
$